A 25.0 cm3 sample of solution containing phenol was treated with 5.0 cm3 of 1 M KBr and 10.0 cm3 of 1.0 M HCl. A platinum electrode was made anodic so that the bromide ion was oxidised to Br2. A constant current of 8.00 mA was passed through the electrolysis cell for 2 min. and 38 s in order to reach the end-point for the titration. The reaction is
Phenol + 3 Br2 Phenol (Br)3 + 3HBr
How many mg of phenol were present in the original sample?
To determine the amount of phenol present in the original sample, we need to use the information provided and perform some calculations.
First, let's calculate the total charge (Q) passed through the electrolysis cell:
Q = I × t
Where:
I = Current = 8.00 mA = 8.00 × 10^(-3) A
t = Time = 2 min. and 38 s = 2 × 60 + 38 = 158 ____ _____ _____ _______ ___ ________ _________ __________ ___.
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