Find the area between the curve and its asy

Question

Find the area between the curve $y^2(4 - x) = x^3$ and its asymptote parallel to y-axis. If the revenue function is given by $\frac{dR}{dx} = 15 + 2x - x^2$ , x being the input, find the maximum revenue. Also find the revenue function R, if the initial revenue is 0.

09 Jan 2026

Answer :

Word Count : 301

The given curve is y²(4 − x) = x³. As x → 4⁻, the denominator (4 − x) → 0⁺ and hence y² → ∞, so the curve has the vertical asymptote x = 4. The curve is symmetric about the x-axis. The horizontal distance between the curve and the __________ ___ _______ _____ __________ ________.
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