Question

समीकरण equation हल कीजिए, जिसके सभी मूल G.P. में हैं।

09 Jan 2026
Answer :
Word Count : 472
समीकरण है: [ x^4 + 15x^3 + 70x^2 + 120x + 64 = 0 ] हमसे कहा गया है कि सभी मूल G.P. (Geometric Progression) में हैं। यदि चार मूल (a, ar, ar^2, ar^3) G.P. में हैं, तो उनका गुणनफल और योग चारों पदों के अनुसार ज्ञात किया जा सकता है। 1. G.P. के गुणनफल और योग के सूत्र: चार पदों की G.P. के लिए (a, ar, ar^2, ar^3): * योग: (a + ar + ar^2 + ar^3 = a(1 + r + r^2 + r^3)) * गुणनफल: (a \cdot ar \cdot ar^2 \cdot ar^3 = a^4 r^6) दी गई समीकरण में: [ x^4 + 15x^3 + 70x^2 + 120x + 64 = 0 ] * यहाँ, चार ________ _________ ____ _________ ___.
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