Word Count : 200

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दो वक्रों (ax^2 + by^2 = 1) और (a'x^2 + b'y^2 = 1) के लम्बवत् प्रतिच्छेदन का अर्थ है कि उनके कोई भी प्रतिच्छेद बिंदु ((x, y)) पर टेंजेंट्स एक-दूसरे के प्रति लम्बवत् हों। पहले, किसी वक्र (F(x, y) = 0) पर टेंजेंट की ढाल (slope) ज्ञात करें: [ ax^2 ___ _________ ____ ______ _________.
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