Word Count : 357

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यहाँ दिए गए डेटा के लिए गाउस पश्चांतर इंटरपोलेशन विधि का प्रयोग करके बहुपद और f(0.45) का मान निकालते हैं। हमारे पास डेटा है: | x | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | | ---- | ---- | ---- | ---- | ---- | ---- | | f(x) | 1.40 | 1.56 | 1.76 | 2.00 | 2.28 | चरण 1: अंतर तालिका बनाना पहली, दूसरी और उच्चतर अंतर निकालते हैं। [ \Delta f_0 = f_1 - f_0 = 1.56 - 1.40 = 0.16 ] ____ _______ _____ ____ ___ ________ ___.
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