Question
Prove that every non-trivial subgroup of a cyclic group has finite index. Hence prove that is not cyclic.
Answer :
Word Count : 278
Let (G) be a cyclic group generated by (g), i.e., (G = \langle g \rangle), and let (H) be a non-trivial subgroup of (G). Since (G) is cyclic, every element of (H) can be written as a power of (g). Let (h) be a non-identity element ____ ____ __________ _________ ________ _____.
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Let (G) be a cyclic group generated by (g), i.e., (G = \langle g \rangle), and let (H) be a non-trivial subgroup of (G). Since (G) is cyclic, every element of (H) can be written as a power of (g). Let (h) be a non-identity element ____ ____ __________ _________ ________ _____.
___ __________ _______ __________ ______ __________ _________ _________ ______ __________ __________ ______.
_______ __________ ___ _______ _______ _________ _________ ________ ____ ________.
__________ ___ ________ ______ ___ _________ ______ __________ _________ _______ _______ ____.
______ __________ ______ ____ _______ ________.
________ __________ _____ ________ ______ __________ _________.
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______ _______ _______ _______ ______ _____ _________ ______.
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