Word Count : 205

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$$ \int \frac{x^2 \cot^{-1}(x^3)}{1+x^6} \, dx $$ सबसे पहले, $x^3 = t$ substitution करें। तो $t = x^3 \implies dt = 3x^2 dx \implies x^2 dx = \frac{dt}{3}$। अब इंटीग्रल बनता है: $$ \int \frac{x^2 \cot^{-1}(x^3)}{1+x^6} \, dx = \int \frac{\cot^{-1}(t) \cdot \frac{dt}{3}}{1 + t^2} = \frac{1}{3} \int \frac{\cot^{-1}(t)}{1+t^2} \, dt ___ ________ _____ ______ ___ _______ ____ ____ _______ _____ _______.
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