Word Count : 590

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यहां हमें एक समतल विद्युत क्षेत्र तरंग का समीकरण दिया गया है: \[ E = 180\pi \cos(10^8 (2\pi x - 100y)) \] अब हम इसे क्रमबद्ध तरीके से हल करेंगे: ### i) आवृत्ति (Frequency) (Hz में) समीकरण में \( E \) को इस रूप में व्यक्त किया गया है: \[ E = 180\pi \cos(10^8 (2\pi x - 100y)) \] यहां, तरंग का समग्र रूप \( \cos(kx - \omega t) \) के जैसा है, जिसमें \( \omega \) angular frequency (कोणीय आवृत्ति) और \( k \) तरंग संख्या (wave number) होते हैं। समीकरण में \( \omega = 10^8 \times 2\pi \) है, क्योंकि \( (kx - \omega t) \) रूप में दिया गया है, और \( t \) का ___ ___ _______ ___ ______ _________ _________.
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