Question
असतत श्रेणियों के लिए समांतर माध्य की दोनों विधियों को उपयोग करते हुए निम्न समंको का समांतर माध्य परिकलित कीजिए :
| अंक | विद्यार्थियों की संख्या |
|---|---|
| 10 | 8 |
| 20 | 21 |
| 30 | 23 |
| 40 | 17 |
| 50 | 15 |
| 60 | 9 |
| 70 | 5 |
| 80 | 2 |
Answer :
Word Count : 392
असतत (वितरित) श्रेणी के लिए समांतर माध्य (Harmonic Mean, H) निकालने की परिभाषा है: $H=\dfrac{N}{\sum \dfrac{f_i}{x_i}}$, जहाँ $N=\sum f_i$। नीचे दिए गए आँकड़ों में अंकों (x) के साथ विद्यार्थियों की संख्या (f) दी है: 10(8), 20(21), 30(23), 40(17), 50(15), 60(9), 70(5), 80(2); कुल $N=100$ पहली विधि: प्रत्यक्ष विधि (Direct Method) इस विधि में प्रत्येक वर्ग के लिए $1/x$ तथा $f/x$ निकाले जाते हैं और $\sum _____ _________ _________ ________ _____ ________ ________ ________ ____.
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असतत (वितरित) श्रेणी के लिए समांतर माध्य (Harmonic Mean, H) निकालने की परिभाषा है: $H=\dfrac{N}{\sum \dfrac{f_i}{x_i}}$, जहाँ $N=\sum f_i$। नीचे दिए गए आँकड़ों में अंकों (x) के साथ विद्यार्थियों की संख्या (f) दी है: 10(8), 20(21), 30(23), 40(17), 50(15), 60(9), 70(5), 80(2); कुल $N=100$ पहली विधि: प्रत्यक्ष विधि (Direct Method) इस विधि में प्रत्येक वर्ग के लिए $1/x$ तथा $f/x$ निकाले जाते हैं और $\sum _____ _________ _________ ________ _____ ________ ________ ________ ____.
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