has bond length
. Calculate the wavenumbers of the first four lines in its microwave spectrum.
[Given: mass of C=12.000 u and mass of N=14.007 u]
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See Answer →The rotational Raman spectrum of a diatomic molecule has the first line of a series of Stokes and anti-Stokes lines at , relative of the
of incident light. What would be its bond length.
Write the basic principle and application of NMR Spectroscopy.
See Answer →In Raman spectra, the Stokes line are more intense than the anti-Stokes lines. Why?
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See Answer →Assuming that the force constants of H-Cl and D-Cl are the same, calculate the fundamental vibration frequency of D-Cl if that of H-Cl is .
Define the following:
i) Mole fraction
ii) Stocks shift
iii) Chromatogram
iv) Half life of radioisotopes
v) Resolving power
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See Answer →A photoelectron spectrum of a compound containing nitrogen (N), aluminium (Al), and fluorine (F) shows three strong peaks at the following binding energies:
Peak X: ~686 eV
Peak Y: ~399 eV
Peak Z: ~73 eV
Find the best option from the choices given below that best explains the relative positioning of these peaks in terms of binding energy.
(i) Peak X corresponds to F 1s electrons, which have the highest binding energy because fluorine’s high electronegativity and small size give its 1s electrons a large effective nuclear attraction. Peak Y is N 1s and Peak Z is Al 2p.
(ii) Nitrogen has more valence electrons than fluorine or aluminium, therefore its peak appears at the highest binding energy.
(iii) The spectrum shows more aluminium atoms than nitrogen or fluorine, so its peak appears at the lowest binding energy due to dilution.
(iv) Aluminium has the highest nuclear charge, so its 2p peak should have the largest binding energy, but shielding effects reverse this trend.
Justify your answer.
What is meant by the Balmer series of hydrogen? What will be the wave number of the longest wavelength in the Balmer series?
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Explain the biochemical basis of muscle fatigue during prolonged physical activity.
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