What is the requirement of the vibrational mode of a molecule to be Raman active?
For a vibrational mode of a molecule to be Raman active, it must involve a change in the polarizability of the molecule during the vibration. Polarizability refers to the ease with which the electron cloud of a molecule can be distorted by an external electric ____ _____ __________ ____ ________ ____ ______ ____ __________ _______ __________ ___.
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The rotational Raman spectrum of a diatomic molecule has the first line of a series of Stokes and anti-Stokes lines at , relative of the
of incident light. What would be its bond length.
What is meant by AX spin system in NMR? Draw a schematic energy level diagram for this system and show the allowed transitions.
Spin-Spin splitting
Predict the number of signal and multiplicity of peaks in the spectrum of the following compounds:
a) 2,5-Dimethylhexane
b) Cyclohexanol
5G services in India are provided at a frequency of . Calculate the wavelength of the radiation.
Electronic transitions are called vertical transitions. Comment.
A photoelectron spectrum of a compound containing nitrogen (N), aluminium (Al), and fluorine (F) shows three strong peaks at the following binding energies:
Peak X: ~686 eV
Peak Y: ~399 eV
Peak Z: ~73 eV
Find the best option from the choices given below that best explains the relative positioning of these peaks in terms of binding energy.
(i) Peak X corresponds to F 1s electrons, which have the highest binding energy because fluorine’s high electronegativity and small size give its 1s electrons a large effective nuclear attraction. Peak Y is N 1s and Peak Z is Al 2p.
(ii) Nitrogen has more valence electrons than fluorine or aluminium, therefore its peak appears at the highest binding energy.
(iii) The spectrum shows more aluminium atoms than nitrogen or fluorine, so its peak appears at the lowest binding energy due to dilution.
(iv) Aluminium has the highest nuclear charge, so its 2p peak should have the largest binding energy, but shielding effects reverse this trend.
Justify your answer.