What does the following C function compute? Discover.
int some fun(int n)
{
if(n%2 == 0)
return 2;
int d, s = sqrt(n);
2
for(d = 3; d <= s; d = d+2)
if(n%d == 0)
return d;
return n;
}
This C function appears to compute the smallest prime factor of a given integer `n`. Here's how it works:
1. If `n` is even (`n % 2 == 0`), the function immediately returns `2`, which is the smallest prime factor of any even number.
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