Question

Using standard five-point formula, solve Laplace equation \nabla^2u=0 in R where R is the square  0 \leq x \leq 1, 0 \leq y \leq 1 subject to the boundary conditions u(x,y) = x^2 - y^2 on x=0 , y=0, y=1
and 3u + 2\frac{\partial u}{\partial x} = x^2 + y^2on x=1.  Assume h=k=1/2.

15 Feb 2024
Answer :
Word Count : 930

To solve Laplace's equation in the square region \( R: 0 \leq x \leq 1, 0 \leq y \leq 1 \) subject to the given boundary conditions, we can use the method of finite differences. We'll discretize the domain into a grid with mesh size \( h = k = 1/2 \).

Let's label the grid points and set up the equations according to the given boundary conditions:

1. At \( x = 0 \), \( y = 0 \), and \( y = 1 \): \( u = x^2 - y^2 \)
2. At \( x = 1 \): \( 3u + 2\frac{\partial u}{\partial x} = x^2 + y^2 \)

Now, let's discretize Laplace's equation \( \nabla^2 u = 0 \) using the five-point stencil method:

\[
\frac{u_{i+1,j} - 2u_{i,j} + u_{i-1,j}}{h^2} + \frac{u_{i,j+1} - 2u_{i,j} + u_{i,j-1}}{k^2} = 0
\]

With the given boundary conditions, we have:

1. \( u_{0,j} = (0)^2 - y_j^2 = -y_j^2 \)
2. \( u_{i,0} = x_i^2 - (0)^2 = x_i^2 \)
3. \( u_{i,N} = x_i^2 - (1)^2 = x_i^2 - 1 \)
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