Question

 Use the Fundamental Theorem of Homomorphism for Groups to prove the following theorem, which is called the Zassenhaus (Butterfly) Lemma:
Let H and K be subgroups of a group G and H' and K' be normal subgroups of H and K, respectively. Then
i) equation
ii) equation

iii) equation equation 
The situation can be represented by the subgroup diagram below, which explains the name ‘butterfly’.

 

Image ignouassignments-ignouacademy-com--p-theorem-89907

 

PART-B (MM: 30 Marks)
(Based on Block 3.)

10 Jan 2026
Answer :
Word Count : 1448
Let’s carefully work through the Zassenhaus (Butterfly) Lemma proof step by step, using the Fundamental Theorem of Homomorphism (First Isomorphism Theorem) for groups. --- ## Step 1: Restating the given setup We have: - \( G \) is a group. - \( H, K \) are subgroups of \( G \). - \( H' \trianglelefteq H \) (\( H' \) normal in \( H \)), \( K' \trianglelefteq K \). We want to prove: 1. \( H'(H \cap K') \trianglelefteq H'(H \cap K) \) 2. \( K'(H' \cap K) \trianglelefteq K'(H \cap K) \) 3. \[ \frac{H'(H \cap K)}{H'(H \cap K')} \simeq \frac{K'(H \cap K)}{K'(H' \cap K)} \simeq \frac{H \cap K}{(H' \cap K)(H \cap K')}. \] The notation \( H'(H \cap K) \) means the product of subgroups \( H' \) and \( H \cap K \) inside \( G \). Since \( H' \trianglelefteq H \), \( H'(H \cap K) \) is a subgroup of \( H \). --- ## Step 2: Prove \( H'(H \cap K') \trianglelefteq H'(H \cap K) \) First, note: - \( H' \trianglelefteq H \) ⇒ \( H' \trianglelefteq H'(H \cap K) \) (since \( H' \) is normal in \( H \) and \( H'(H \cap K) \leq H \)). Also, \( H \cap K' \) is normal in something — we should check: \( K' \trianglelefteq K \) ⇒ \( H \cap K' \trianglelefteq H \cap K \) (because for any \( x \in H \cap K \), conjugation by \( x \) is inside \( K \) and preserves \( K' \) since \( K' \trianglelefteq K \), and \( x \) also in \( H \) so conjugates \( H \cap K' \) within \( H \cap K' \)). So \( H \cap K' \trianglelefteq H \cap K\). Thus \( H'(H \cap K') \) is a subgroup (product of two subgroups \( H' \) and \( H \cap K' \) with \( H' \trianglelefteq H \) and \( H \cap K' \leq H \)). Since \( H' \trianglelefteq H \) and \( H \cap K' \trianglelefteq H \cap K \), normality in \( H'(H \cap K) \) requires checking: Take \( a ____ ________ _________ _____ ____ __________ __________ ______ _____ _______ ____.
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