Question
Use secant method to determine the root of the equation cos x - xex = 0. Take the initial approximation as x0 = 0, x1 = 1 and perform two iterations of the method.
Answer :
Word Count : 115
Let $f(x)=\cos x - x e^{x}$. With $x_0=0,\;x_1=1$ we have $$ f(0)=\cos0-0\cdot e^{0}=1, \qquad f(1)=\cos1-1\cdot e^{1}\approx0.5403023059-2.7182818285=-2.1779795226. $$ Secant formula $x_{2}=x_{1}-f(x_{1})\dfrac{x_{1}-x_{0}}{f(x_{1})-f(x_{0})}$. Substituting the numbers, $$ x_{2}=1-(-2.1779795226)\frac{1-0}{-2.1779795226-1} =1-\frac{2.1779795226}{3.1779795226}\approx1-0.685334\approx0.314666. $$ Now _________ _________ ____ ___ ________ _______ ________ _____ ______ ____ ___ __________.
___ __________ ______ _____ ________.
_____ ______ __________ _______ _________ __________ _____ __________ ____ __________ _____ ___.
________ __________ __________ ______ ___ ________ ____ __________ ___.
_________ ___ __________ _____ ____ ___ _____ ______ ____ _______ _______ _________.
_______ ___ ___ _________ _________ _____ _____.
____ __________ _______ ___ ____.
__________ _________ ______ ____ ____ _____.
______ _________ ____ ______ ____ _____ ____ _____.
______ _______ ___ ___ ___ __________ __________ ________ ____ ______ _________.
Get Full Answer on WhatsApp
Let $f(x)=\cos x - x e^{x}$. With $x_0=0,\;x_1=1$ we have $$ f(0)=\cos0-0\cdot e^{0}=1, \qquad f(1)=\cos1-1\cdot e^{1}\approx0.5403023059-2.7182818285=-2.1779795226. $$ Secant formula $x_{2}=x_{1}-f(x_{1})\dfrac{x_{1}-x_{0}}{f(x_{1})-f(x_{0})}$. Substituting the numbers, $$ x_{2}=1-(-2.1779795226)\frac{1-0}{-2.1779795226-1} =1-\frac{2.1779795226}{3.1779795226}\approx1-0.685334\approx0.314666. $$ Now _________ _________ ____ ___ ________ _______ ________ _____ ______ ____ ___ __________.
___ __________ ______ _____ ________.
_____ ______ __________ _______ _________ __________ _____ __________ ____ __________ _____ ___.
________ __________ __________ ______ ___ ________ ____ __________ ___.
_________ ___ __________ _____ ____ ___ _____ ______ ____ _______ _______ _________.
_______ ___ ___ _________ _________ _____ _____.
____ __________ _______ ___ ____.
__________ _________ ______ ____ ____ _____.
______ _________ ____ ______ ____ _____ ____ _____.
______ _______ ___ ___ ___ __________ __________ ________ ____ ______ _________.
Get Full Answer on WhatsApp
IGNOU NEWS
Assignment Submission Last Date Extended Till 30 June 2026 Click Here★★★IGNOU June 2026 TEE Date Sheet Released Click Here★★★