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We will use Mathematical Induction to prove the given formula: \[ 1^2 + 2^2 + 3^2 + ... + n^2 = \frac{n(2n+1)(n+1)}{6} \] ### Step 1: Base Case (n = 1) For \( n = 1 \), \[ 1^2 = \frac{1(2(1) + 1)(1+1)}{6} \] \[ 1 = \frac{1(2+1)(2)}{6} = \frac{1 \times 3 \times 2}{6} = \frac{6}{6} = _________ __________ ____ _____ ______ __________.
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