Question
Use a binary-coded Genetic algorithm (GA) to minimize the function f ( x1 , x2 ) = x1+ x2 + 2x12- x22+ x1 , x2, in the range of 0 x1, x2
5 . Use a random population of size N = 6 , a single point crossover with probability Pc=1 and neglect mutation. Assume 3 bits for each variable and thus the GA-string will be 6- bits long. Show only one iteration by hand calculation.
Answer :
Word Count : 728
Let's go step by step and perform one iteration of the Binary-Coded Genetic Algorithm (GA) to minimize the function: \[ f(x_1, x_2) = x_1 + x_2 + 2x_1^2 - x_2^2 \] within the range 0 ≤ x₁, x₂ ≤ 5 using Binary-Coded GA. --- ### Step 1: Encoding Variables into Binary Strings We assume 3 bits for each variable. Since each variable takes values between 0 and 5, we map the binary numbers to real values. Using 3-bit binary encoding, the mapping is: \[ x = \frac{\text{Binary Code}}{(2^3 - 1)} \times 5 = \frac{\text{Binary Code}}{7} \times 5 \] | Binary (3-bit) | Decimal Value | Scaled Value \(x = \frac{\text{Decimal}}{7} \times 5\) | |---------------|--------------|----------------------------------| | 000 | 0 | 0 | | 001 | 1 | 0.714 | | 010 | 2 | 1.429 | | 011 | 3 | 2.143 | | 100 | 4 | 2.857 | | 101 | 5 | 3.571 | | 110 | 6 | 4.286 | | 111 | 7 | 5.000 | Each chromosome consists of 6 bits (3 bits for \(x_1\) and 3 ___ ____ _________ _______ ___ ____ __________ ________ ___ _____ ___.
___ ________ __________ ______ ___ ____ ____ __________.
_____ _____ ___ ________ __________ _______.
___ ____ _________ ___ _____ ___ ________ ____ ___ _______ ______ _____.
_________ ________ _________ ____ ______ _____ _______ ____ ____.
_____ ________ ____ ____ ______ _____.
_________ ______ ____ ______ ___ _________ __________ _______ _____ ____ ____ _______.
______ _________ _________ ____ __________ ____.
__________ _________ _______ ___ _________ _______.
_____ _________ __________ ____ _________ ___ ______ _______ ________ ______.
___ ___ ______ _____ _______ _______ ____ _________ __________.
__________ _____ ____ _____ _________ _________ ___.
_______ _______ ________ ______ ____ __________ __________.
_____ ___ _______ ___ ___ _________ ___ ____.
_______ _______ _________ ______ _____ ____ __________ ___ _______ _________ _________.
__________ ______ ____ _____ ___ ____ _______ ___ ______.
______ ____ __________ _________ _____ ______ __________.
_____ _______ ___ _______ ___ _____ _________.
______ ________ ___ _______ ____ ________ _______ ______ _______.
_________ ______ ________ _____ ___ ____ ____ __________ _________ _______.
_________ __________ _______ ________ _______ __________ ________.
__________ ___ ______ _____ _________.
____ __________ _____ _____ ___ ______ ____.
_____ ________ ___ _____ ___ ____ _________ ________ ___ _________ ___.
_____ ____ ________ _______ __________ _______ __________ ________.
_______ ______ _________ _________ ________ _____.
______ ______ ___ _____ _______ ____ ______ _____ ___ __________ ______.
____ _______ _________ ________ ____ _________ _______ ______ ______.
__________ ____ ______ ________ ____ ______ _______.
________ ____ __________ ___ ______ _____ __________ ______ _______ ______.
___ ___ __________ ______ ___.
___ _____ ________ _________ ______ _________ ________ _____.
_______ ___ _____ ____ __________.
____ ______ ______ ___ ______ ___ ______ ___.
_____ ______ ______ ________ ___ __________.
___ ______ ______ ____ ___ ______ _______ ______.
__________ _________ _______ _____ __________ __________ _______.
_____ ____ ___ ____ _________ ________ ___.
__________ ______ _______ _________ ________ _______ ________ __________ ______ _______ ___ _____.
____ ____ ________ ________ __________ _______ ______ ________ __________ ___ ____ _____.
_______ _______ ________ ___ _____ ___ _____.
_____ ______ _____ _____ ___ _________ ________ _______ ____ _______ _______.
_________ ________ _________ ___ __________ ____ _________.
_____ ______ _______ __________ _____ ________ _______.
_______ _____ _____ _________ ______ _________ ______ _________ __________.
________ ______ ________ ____ _________ ______ _________ _________.
___ ________ __________ ______ _________ ________ __________.
______ _________ ___ _____ ___ _____ _____.
_________ ___ _________ _____ __________ _______.
________ ______ _________ _____ _________ ______ _________ ____ ________ ___ ___.
_______ __________ ___ __________ ______ ______ ____ __________ _______.
_________ _______ ___ ___ ___ ________ ___ __________ ___ _______.
___ _________ _____ _________ _______ ________ _____ _______ _________.
___ ___ ___ ______ ___ _________ _____ __________.
________ _____ _________ ________ ___ _________ __________ __________ __________ _____ _____.
____ _______ ______ ______ _____ _____ ________ ______ __________ ______.
________ ___ __________ __________ _________ __________ ______ _________ ____ _____ ___ ____.
_______ _________ ______ ____ _______ _______ ______ ____ _____.
______ ___ _________ ______ ___ ________ ______ _________ ________ ________.
_________ __________ ___ ____ ____ _____ ________ ____ ________ _______.
_______ _________ ________ __________ _____ ______ ________ ______ _______ ______ ___ __________.
____ ________ __________ ___ ___ _______ ____ _______ ____ ______ ___.
______ ________ _______ _________ ___.
____ ______ ______ ________ ________ __________ ______ ________ ___ _____ ______.
Get Full Answer on WhatsApp
Let's go step by step and perform one iteration of the Binary-Coded Genetic Algorithm (GA) to minimize the function: \[ f(x_1, x_2) = x_1 + x_2 + 2x_1^2 - x_2^2 \] within the range 0 ≤ x₁, x₂ ≤ 5 using Binary-Coded GA. --- ### Step 1: Encoding Variables into Binary Strings We assume 3 bits for each variable. Since each variable takes values between 0 and 5, we map the binary numbers to real values. Using 3-bit binary encoding, the mapping is: \[ x = \frac{\text{Binary Code}}{(2^3 - 1)} \times 5 = \frac{\text{Binary Code}}{7} \times 5 \] | Binary (3-bit) | Decimal Value | Scaled Value \(x = \frac{\text{Decimal}}{7} \times 5\) | |---------------|--------------|----------------------------------| | 000 | 0 | 0 | | 001 | 1 | 0.714 | | 010 | 2 | 1.429 | | 011 | 3 | 2.143 | | 100 | 4 | 2.857 | | 101 | 5 | 3.571 | | 110 | 6 | 4.286 | | 111 | 7 | 5.000 | Each chromosome consists of 6 bits (3 bits for \(x_1\) and 3 ___ ____ _________ _______ ___ ____ __________ ________ ___ _____ ___.
___ ________ __________ ______ ___ ____ ____ __________.
_____ _____ ___ ________ __________ _______.
___ ____ _________ ___ _____ ___ ________ ____ ___ _______ ______ _____.
_________ ________ _________ ____ ______ _____ _______ ____ ____.
_____ ________ ____ ____ ______ _____.
_________ ______ ____ ______ ___ _________ __________ _______ _____ ____ ____ _______.
______ _________ _________ ____ __________ ____.
__________ _________ _______ ___ _________ _______.
_____ _________ __________ ____ _________ ___ ______ _______ ________ ______.
___ ___ ______ _____ _______ _______ ____ _________ __________.
__________ _____ ____ _____ _________ _________ ___.
_______ _______ ________ ______ ____ __________ __________.
_____ ___ _______ ___ ___ _________ ___ ____.
_______ _______ _________ ______ _____ ____ __________ ___ _______ _________ _________.
__________ ______ ____ _____ ___ ____ _______ ___ ______.
______ ____ __________ _________ _____ ______ __________.
_____ _______ ___ _______ ___ _____ _________.
______ ________ ___ _______ ____ ________ _______ ______ _______.
_________ ______ ________ _____ ___ ____ ____ __________ _________ _______.
_________ __________ _______ ________ _______ __________ ________.
__________ ___ ______ _____ _________.
____ __________ _____ _____ ___ ______ ____.
_____ ________ ___ _____ ___ ____ _________ ________ ___ _________ ___.
_____ ____ ________ _______ __________ _______ __________ ________.
_______ ______ _________ _________ ________ _____.
______ ______ ___ _____ _______ ____ ______ _____ ___ __________ ______.
____ _______ _________ ________ ____ _________ _______ ______ ______.
__________ ____ ______ ________ ____ ______ _______.
________ ____ __________ ___ ______ _____ __________ ______ _______ ______.
___ ___ __________ ______ ___.
___ _____ ________ _________ ______ _________ ________ _____.
_______ ___ _____ ____ __________.
____ ______ ______ ___ ______ ___ ______ ___.
_____ ______ ______ ________ ___ __________.
___ ______ ______ ____ ___ ______ _______ ______.
__________ _________ _______ _____ __________ __________ _______.
_____ ____ ___ ____ _________ ________ ___.
__________ ______ _______ _________ ________ _______ ________ __________ ______ _______ ___ _____.
____ ____ ________ ________ __________ _______ ______ ________ __________ ___ ____ _____.
_______ _______ ________ ___ _____ ___ _____.
_____ ______ _____ _____ ___ _________ ________ _______ ____ _______ _______.
_________ ________ _________ ___ __________ ____ _________.
_____ ______ _______ __________ _____ ________ _______.
_______ _____ _____ _________ ______ _________ ______ _________ __________.
________ ______ ________ ____ _________ ______ _________ _________.
___ ________ __________ ______ _________ ________ __________.
______ _________ ___ _____ ___ _____ _____.
_________ ___ _________ _____ __________ _______.
________ ______ _________ _____ _________ ______ _________ ____ ________ ___ ___.
_______ __________ ___ __________ ______ ______ ____ __________ _______.
_________ _______ ___ ___ ___ ________ ___ __________ ___ _______.
___ _________ _____ _________ _______ ________ _____ _______ _________.
___ ___ ___ ______ ___ _________ _____ __________.
________ _____ _________ ________ ___ _________ __________ __________ __________ _____ _____.
____ _______ ______ ______ _____ _____ ________ ______ __________ ______.
________ ___ __________ __________ _________ __________ ______ _________ ____ _____ ___ ____.
_______ _________ ______ ____ _______ _______ ______ ____ _____.
______ ___ _________ ______ ___ ________ ______ _________ ________ ________.
_________ __________ ___ ____ ____ _____ ________ ____ ________ _______.
_______ _________ ________ __________ _____ ______ ________ ______ _______ ______ ___ __________.
____ ________ __________ ___ ___ _______ ____ _______ ____ ______ ___.
______ ________ _______ _________ ___.
____ ______ ______ ________ ________ __________ ______ ________ ___ _____ ______.
Get Full Answer on WhatsApp
IGNOU NEWS
Assignment Submission Last Date Extended Till 30 June 2026 Click Here★★★IGNOU June 2026 TEE Date Sheet Released Click Here★★★