Question

The weight on a vertical spring undergoes forced vibrations according to the following equation:

\frac{d^{2}x}{dt^{2}}+4x =8sin\; \omega t

where x is the displacement from the equilibrium position and \omega > 0 is a constant. If at t = 0, x = 0 and \frac{dx}{dt}=0,  calculate x as a function of t.

08 Feb 2021
Answer :
Word Count : 123
The given second-order differential equation is: \[ \frac{d^{2}x}{dt^{2}} + 4x = 8\sin(\omega t) \] with initial conditions: \[ x(0) = _________ ________ ___ _______ ________.
________ ___ _____ _____ _________ ________ ____ ______ _________ ____.
______ ________ _____ ______ __________ _____ _______ ___.
________ ___ ___ _______ _____ ___ __________.
________ ____ __________ ___ ______ ________ ____ ______ _______ __________ ____ __________.
___ ________ ______ ____ _________ ______.
_______ ____ _____ ________ ____ __________ ______ ______ _______ ______.
_____ __________ _________ ______ ___.
_______ __________ __________ _________ ________ _____ _________ ______.
_________ _____ ______ ________ _________ __________ _______ ________ _________ _____.
_______ _________ __________ __________ ____.
______ _________ _____ __________ _______ ___ ___ _____ ____ _______.
_______ _____ _____ _________ _________.
_____ ___.
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