Question

 The rotational Raman spectrum of a diatomic molecule has the first line of a series of Stokes and anti-Stokes lines at equation, relative of the equation of incident light. What would be its bond length. 

21 Jan 2026
Answer :
Word Count : 513
For a diatomic molecule, the rotational Raman lines are spaced by ( 2B ), where ( B ) is the rotational constant in wavenumbers (( \text{cm}^{-1} )). The first Stokes line corresponds to a transition ( J = 0 \to J = 2 ), giving a shift of ( \Delta \tilde{\nu} = 6B ). Given: [ \Delta \tilde{\nu} = 346 \ \text{cm}^{-1} = 6B ] [ B = \frac{346}{6} = 57.6667 \ \text{cm}^{-1} \approx 57.67 \ \text{cm}^{-1} ] The rotational constant ( B ) is related to the bond length ( r ) by: [ B = \frac{h}{8 \pi^2 c I} \quad _________ ___ _________ ________ ___.
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