Question

The roots of x^{3}-8x-3=0 are given by x=\frac{8\pm\sqrt{64+12}}{2}.

11 Mar 2024
Answer :
Word Count : 149
To solve the cubic equation \( x^3 - 8x - 3 = 0 \) numerically, we are provided the formula for its roots: \[ x = \frac{8 \pm \sqrt{64 + 12}}{2} \] Let's calculate the values step ____ _________ ___ _____ ____ _________ _______.
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