The resistance of a conductivity cell filled with an electrolytic solution is observed to be 180 Ω. If the resistance of 0.1M KCl solution taken in the same cell was found to be 72 Ω calculate the conductivity of the given solution. (Given: The conductivity of 0.1 M KCl solution = 1.29 S m-1 ).

Given,

Resistance = 180 Ω.

The conductivity of 0.1 M KCl solution = 1.29 S m^-1

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