Question
The Lagrangian of a bead of m moving without friction along a wire bent in the shape of a parabola in the X-Y pane with is given by:
Answer :
Word Count : 219
The Lagrangian of the bead is given as: [ L = \frac{1}{2} m (1 + 4x^2) \dot{x}^2 - mg x^2 ] We solve using the Euler-Lagrange equation: [ \frac{d}{dt} \left( \frac{\partial L}{\partial \dot{x}} \right) - \frac{\partial L}{\partial x} = 0 ] First, calculate ________ ________ ____ _________ ______ ____ ___.
____ ___ _________ _______ ________ ________ ________ _______.
____ _____ ______ ________ __________ ______ ________ _____.
___ ___ _______ ___ _____ __________ _____.
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_______ ___ ___ ______ ___ ___ _____ _______.
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_____ ___ _____ _________ __________ __________ ______.
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___ _________ ________ _______ ___ __________ ________ _________ _________ __________ ____.
__________ __________ __________ ___ _________ __________.
_______ _____ _____ ____ _____ _______ ___ _____ ___.
_____ __________ ____ __________ _____ ________ _______ ________ ___ ________ __________ _________.
______ _____ _________ ______ ________ _________ __________.
_______ ________ _______ ___ ___ _______ __________ ____.
_____ _____ _________ _________ ______ _________ ________ ________ __________ ____ ____.
___ ______ __________ _______ ______ ______.
______ ___ _______ _______ ________ ________ ____ ___ _______ ___.
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The Lagrangian of the bead is given as: [ L = \frac{1}{2} m (1 + 4x^2) \dot{x}^2 - mg x^2 ] We solve using the Euler-Lagrange equation: [ \frac{d}{dt} \left( \frac{\partial L}{\partial \dot{x}} \right) - \frac{\partial L}{\partial x} = 0 ] First, calculate ________ ________ ____ _________ ______ ____ ___.
____ ___ _________ _______ ________ ________ ________ _______.
____ _____ ______ ________ __________ ______ ________ _____.
___ ___ _______ ___ _____ __________ _____.
____ _______ __________ __________ _____ ________ _________ ________.
_______ _________ ________ _________ _____ ____ __________ __________ _______.
_________ _________ __________ ______ ____ ______ _______.
_______ ___ ___ ______ ___ ___ _____ _______.
________ ____ _________ ___ ___ ________ ________ __________ ______ _______ ___.
_____ ___ _____ _________ __________ __________ ______.
________ ___ ______ _____ _____ _____.
_____ ______ __________ ______ _________ ______ ______ __________ __________ ____.
___ _________ ________ _______ ___ __________ ________ _________ _________ __________ ____.
__________ __________ __________ ___ _________ __________.
_______ _____ _____ ____ _____ _______ ___ _____ ___.
_____ __________ ____ __________ _____ ________ _______ ________ ___ ________ __________ _________.
______ _____ _________ ______ ________ _________ __________.
_______ ________ _______ ___ ___ _______ __________ ____.
_____ _____ _________ _________ ______ _________ ________ ________ __________ ____ ____.
___ ______ __________ _______ ______ ______.
______ ___ _______ _______ ________ ________ ____ ___ _______ ___.
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