Suppose two friends Anjali and Prabhat trying to meet for a date to have lunch say
between 2 pm to 3 pm. Suppose they follow the following rules for this meeting:
• Each of them will reach either on time or 10 minutes late or 20 minutes late or 30
minutes late or 40 minutes late or 50 minutes late or 1 hour late. All these arrival
times are equally likely for both of them.
• Whoever of them reaches first will wait for the other to meet only for 10 minutes. If
within 10 minutes the other does not reach, he/she leaves the place and they will
not meet.
Find the probability of their meeting.
To find the probability of Anjali and Prabhat meeting within the specified time frame, we can break down the problem into cases based on when they arrive and calculate the probability for each case. We'll consider both Anjali and Prabhat's arrival times independently, and then find the overall probability of them meeting within 10 minutes. Since all arrival times are equally likely for both of them, we can treat their arrivals as independent events.
Let's analyze the possibilities:
-
Both Anjali and Prabhat arrive on time (neither is late):
- Probability of Anjali arriving on time: 1/7 (since there are 7 equally likely arrival times)
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