Solve by Jacobi’s method, the following system of linear equations:

To solve the system of linear equations using Jacobi's method, we need to rewrite the equations in the form:

x₁ = (b₁ - a₁₂ x₂ - a₁₃ x₃) / a₁₁
x₂ = (b₂ - a₂₁ x₁ - a₂₃ x₃) / a₂₂
x₃ = (b₃ - a₃₁ x₁ - a₃₂ x₂) / a₃₃

where aᵢⱼ and bᵢ are the coefficients of the system, and x₁, x₂, and x₃ are the unknowns. We then iterate the equations until convergence. Let's write the system in the required form:

x₁ = (-z₂ + x₃ - 1) / 2
x₂ = (6 - x₁ + x₃) / 2
x₃ = (-z₂ - 3 + x₁) / 2

We can now start the iterative process. Let x₁⁰, x₂⁰, and x₃⁰ be the initial approximations, which we can set to zero. Then, at each iteration k, we compute new values of x₁, x₂, and x₃ using the above equations and the values of x₁ᵏ₋₁, x₂ᵏ₋₁, and x₃ᵏ₋₁ from the previous iteration:

x₁ᵏ = (-z₂ + x₃ᵏ₋₁ - 1) / 2
x₂ᵏ = (6 - x₁ᵏ₋₁ + x₃ᵏ₋₁) / 2
x₃ᵏ = (-z₂ - 3 + x₁ᵏ₋₁) / 2

We repeat this process until the values of x₁, x₂, and x₃ converge to a solution. __________ ________ _________ __________ ___ _______ _________ ______ ___ ___.
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