Question
Sodium metal crystallizes in the bcc structure. The metal has atomic weight 23 and density . Calculate the cubic lattice parameter a and the shortest distance between atoms in this structure.
Answer :
Word Count : 185
For a body-centered cubic (bcc) structure, there are 2 atoms per unit cell. The density formula is: [ \rho = \frac{n \cdot A}{V_c \cdot N_A} ] Where: (\rho = 971 \text{ kg/m}^3), (n = 2), (A = 23 \text{ g/mol} = 0.023 \text{ kg/mol}), (N_A = __________ ____ _______ _____ _________ ____ ________.
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For a body-centered cubic (bcc) structure, there are 2 atoms per unit cell. The density formula is: [ \rho = \frac{n \cdot A}{V_c \cdot N_A} ] Where: (\rho = 971 \text{ kg/m}^3), (n = 2), (A = 23 \text{ g/mol} = 0.023 \text{ kg/mol}), (N_A = __________ ____ _______ _____ _________ ____ ________.
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