Question
Show that , the lagrange's form of remainder in the Maclaurin series expansion of e4x, tends to zero as
. Hence obtain the Maclaurin's infinite expansion for e4x.
Answer :
Word Count : 130
For the function (f(x) = e^{4x}), the Maclaurin series expansion is [ f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \dots + \frac{f^{(n)}(0)}{n!}x^n + R_n(x), ] _____ _____ _______ ________ ___ _________.
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For the function (f(x) = e^{4x}), the Maclaurin series expansion is [ f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \dots + \frac{f^{(n)}(0)}{n!}x^n + R_n(x), ] _____ _____ _______ ________ ___ _________.
_______ ________ _____ ___ _______ ____.
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