Question
Show that , the lagrange's form of remainder in the Maclaurin series expansion of e4x, tends to zero as
. Hence obtain the Maclaurin's infinite expansion for e4x.
Answer :
Word Count : 130
For the function (f(x) = e^{4x}), the Maclaurin series expansion is [ f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \dots _______ ________ _________ _________ ____ ________ ______ _____ ________ _______ ____ ___.
__________ __________ ___ _____ __________ _____ _________ ______ ________ __________ __________.
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________ _______ _________ __________ __________ __________ _______ ______ __________ __________.
____ ___ ______ _________ _________ _____ ____ ________ ____ _________.
___ ____ _______ _____ ________ _______ ____ ________ ____ _______.
______ _____ ___ ____ ________.
_______ _____ ____ _____ __________ ______ __________ _______ _________ ___ ___ __________.
_______ __________.
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For the function (f(x) = e^{4x}), the Maclaurin series expansion is [ f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \dots _______ ________ _________ _________ ____ ________ ______ _____ ________ _______ ____ ___.
__________ __________ ___ _____ __________ _____ _________ ______ ________ __________ __________.
_____ _________ ______ ____ ___ _______ _______ _______ ____.
_______ ____ _______ _____ _________ ________ __________ _______ _______ _________ ________.
_____ _______ _____ _______ _________ _____ __________ _____ ________ __________ __________.
_____ _______ ______ ___ _________ ______.
________ _______ _________ __________ __________ __________ _______ ______ __________ __________.
____ ___ ______ _________ _________ _____ ____ ________ ____ _________.
___ ____ _______ _____ ________ _______ ____ ________ ____ _______.
______ _____ ___ ____ ________.
_______ _____ ____ _____ __________ ______ __________ _______ _________ ___ ___ __________.
_______ __________.
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