Word Count : 66

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Put $r=\sqrt{x^2+y^2}$. For $(x,y)\neq(0,0)$ we have by the AM–GM inequality $$ x^2y^2 \le\left(\frac{x^2+y^2}{2}\right)^2=\frac{(x^2+y^2)^2}{4}. $$ Hence $$ ______ ____ ___ _________ _________ __________ ________ _________ ____ _______.
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