Question
Show that the following function f is differentiable at (0,0):
Answer :
Word Count : 66
Put $r=\sqrt{x^2+y^2}$. For $(x,y)\neq(0,0)$ we have by the AM–GM inequality $$ x^2y^2 \le\left(\frac{x^2+y^2}{2}\right)^2=\frac{(x^2+y^2)^2}{4}. ________ __________ ____ ________ ____ _____ ________ ____.
_____ ____ ________ __________ ___ ___ _______ _______.
_______ _____ __________ _____ _______ ________ ________ ___ ________ ____.
_____ _____ ____ __________ _______ __________ _______ ____ ____ ____ ___.
__________ ________ _______ ______ ______ ________ __________.
______ _____ _____ __________ ___ _____ _______ _________.
________.
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Put $r=\sqrt{x^2+y^2}$. For $(x,y)\neq(0,0)$ we have by the AM–GM inequality $$ x^2y^2 \le\left(\frac{x^2+y^2}{2}\right)^2=\frac{(x^2+y^2)^2}{4}. ________ __________ ____ ________ ____ _____ ________ ____.
_____ ____ ________ __________ ___ ___ _______ _______.
_______ _____ __________ _____ _______ ________ ________ ___ ________ ____.
_____ _____ ____ __________ _______ __________ _______ ____ ____ ____ ___.
__________ ________ _______ ______ ______ ________ __________.
______ _____ _____ __________ ___ _____ _______ _________.
________.
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का व्यापक हल प्राप्त कीजिए।
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