Question
Prove that the linear fractional transformation maps the circle
into itself. Also prove
that f(z) is conformal in .
Answer :
Word Count : 163
Consider the linear fractional transformation [ \phi(z)=\frac{2z-1}{2-z}. ] First, we show that the circle (C:\ |z|=1) is mapped into itself. Let (|z|=1). Then (\bar z = 1/z). Compute [ |\phi(z)|^2=\phi(z)\overline{\phi(z)} =\frac{2z-1}{2-z}\cdot \frac{2\bar ________ __________ ____ ____ _______ _________ __________.
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_________.
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Consider the linear fractional transformation [ \phi(z)=\frac{2z-1}{2-z}. ] First, we show that the circle (C:\ |z|=1) is mapped into itself. Let (|z|=1). Then (\bar z = 1/z). Compute [ |\phi(z)|^2=\phi(z)\overline{\phi(z)} =\frac{2z-1}{2-z}\cdot \frac{2\bar ________ __________ ____ ____ _______ _________ __________.
_________ ____ __________ __________ __________ _________ __________ ___ _______ _____.
_________ ______ ______ _____ _________ _________ _____.
___ ______ ___ ______ ________ __________ ____ ______.
_________ ____ _______ ______ _____ ______ _________ __________ ______ ______ __________.
______ _____ _______ ________ ___.
__________ ____ ______ ______ _______ ____.
____ ________ _______ _____ ______ _______ ________.
______ ___ _________ ___ ________ _____ ________ __________ _______.
______ ___ __________ ______ __________.
__________ _______ ____ _____ __________ __________ ____ ____ ________ __________ _____ ________.
_____ __________ __________ ____ ________ ___ ______ ______.
__________ ______ ____ _________ _______ __________ ______ ________.
_______ ____ ________ ______ _____ ______ ________.
___ _______ ______ ____ ____ ________.
_________ _____ _________ ________ ________ _____ ___ _______.
_______ _____ ________ ___ ________ ___.
_________.
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