Word Count : 361

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The function given is: \[ f(x) = \frac{x^2 - 5x + 4}{x^2 - 16}, \quad x \neq 4 \] We need to determine whether the function is continuous at \( x = 4 \). ### Step 1: Factorization Let's first factor both the numerator and the denominator. - The numerator is \( x^2 - 5x + 4 \), which factors as: \[ x^2 - 5x + 4 = (x - 4)(x - 1) \] - The denominator is \( x^2 - 16 \), which is a difference of squares: \[ ______ _______ _____ ____ __________ _________ _________.
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