In an iron determination from the same amount of sample, the five replicate results were obtained: 20.1, 19.6, 20.0 and 19.9 and 20.4 mg iron.
Calculate the standard deviation, variance, standard deviation of mean, coefficient of variation and relative standard deviation in ppm of the given data.
First, we list the data points: 20.1, 19.6, 20.0, 19.9, and 20.4 mg. Step 1: Calculate the mean ((\bar{x})) [ \bar{x} = \frac{20.1 + 19.6 + 20.0 + 19.9 + 20.4}{5} = \frac{99.9}{5} = 19.98 , \text{mg} ] Step 2: Calculate deviations from the mean and square them [ (20.1 - 19.98)^2 = (0.12)^2 = 0.0144 ] [ (19.6 ______ ______ _________ ______ _________ _______ _____ ______ _____ _________ ___.
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(a) Evaluate the following limit.
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(a) If A = 
then show that
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