Question

If H_{2} is a Hermite polynomial of degree n, then show that: 

H_{n}^{n}=4n(n=1)H_{n-2}

 

22 Mar 2023
Answer :
Word Count : 249

We can prove this using the generating function of Hermite polynomials. The generating function for Hermite polynomials is given by:

e^(2xt-t^2) = \sum _(n=0)^\infty H_n(x) (t^n/n!)

Differentiating both sides of this equation n times with respect to t, we get:

(\vartheta /\vartheta t)^n (e^(2xt-t^2)) = \sum _(k=n)^\infty H_k(x) (k!/[(k-n)!n!]) t^(k-n)

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