Question
If F is a field, show that U(F[x]) = F.
Answer :
Word Count : 262
Let $F$ be a field and consider the polynomial ring $F[x]$. The set $U(F[x])$ denotes the group of units in $F[x]$, that is, the set of all polynomials in $F[x]$ which have multiplicative inverses within $F[x]$. Suppose $f(x) \in F[x]$ is a unit. Then there exists $g(x) \in F[x]$ such that $$ ___ ________ ____ ______ __________ _____.
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Let $F$ be a field and consider the polynomial ring $F[x]$. The set $U(F[x])$ denotes the group of units in $F[x]$, that is, the set of all polynomials in $F[x]$ which have multiplicative inverses within $F[x]$. Suppose $f(x) \in F[x]$ is a unit. Then there exists $g(x) \in F[x]$ such that $$ ___ ________ ____ ______ __________ _____.
____ _____ _________ ____ ____ _______ _________ ___.
__________ ___ _____ _______ ___ ___ _________ _________ ____ __________ _______.
_____ _________ _______ ________ ________ _________.
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____ _______ ____ ___ __________.
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