Given for a single wall carbon nanotube that rolls on, chiral vector i

Question

Given for a single wall carbon nanotube that rolls on, chiral vector is r = na,+ mas, Find out the chiral angle and diameter of CNT with (n, m) = (5,5). (5)

05 May 2025

Answer :

Word Count : 267

For a single-walled carbon nanotube (SWCNT), the chiral vector is defined as:

$$
\mathbf{r} = n \mathbf{a}_1 + m \mathbf{a}_2
$$

Where $\mathbf{a}_1$ and $\mathbf{a}_2$ are the unit vectors of the graphene lattice, and $n$ and $m$ are integers that define the chirality of the nanotube.

The chiral angle $\theta$ is the angle between the chiral vector and the graphene’s zigzag direction (which corresponds __________ _________ _________ ____ __________ _______ _________ ____ ___.
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