Question

For a simple harmonic oscillator, show that the expectation value of x, defined as   < x>\: _{mu}=\int \Psi m^{^{^{^{*}}}}\: \: (x)dx \: is\sqrt{\frac{1}{2a^{2}}}

for the n = 0 and m =1 states. Use the result

\int_{0}^{\infty }x\: ^{^{\frac{1}{2}}}\: e^{-x}dx= \sqrt{\pi }.

06 Feb 2021
Answer :
Word Count : 196
To numerically solve the expectation value of \( x \) for a simple harmonic oscillator, we will proceed as follows: ### Given Information: 1. The expectation value of \( x \) is _____ _________ _____ _________ __________ ________ ___ ___ _______ _______ _____ _________.
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_________ ______ ____ ____ _____.
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________ _________ ___ _________ _________.
_______ _______ _________ _______ ____ ___ ______ _________ _________.
_________ ________ __________ _____ ____.
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_______ ________ ________ __________ ____ _______ _______ ___ _______ ____ ___ ______.
______ ___ ______ ________ ________ ____ ____ _______ ___.
______ ____ ___ _________ ______ ___ _______ ________ _____.
_______ _____ __________.
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