Question

Find the radius of convergence of the following series

i) \sum_{k=1}^{\infty}\frac{(-1)^{k+1}}{k!} (z-1-i)^k

ii) \sum_{k=1}^{\infty}\left ( \frac{6k + 1}{2k + 5} \right )^k\left ( z - 2i \right )^k

07 Feb 2024
Answer :
Word Count : 106

i) \sum_{k=1}^{\infty}\frac{(-1)^{k+1}}{k!} (z-1-i)^k

This is a Taylor series expansion of the function e^{-(z-1-i)} centered at 1+i. 

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