Find the following limits:
(i)
(ii)
Let us solve both limits step-by-step manually and numerically, without using Python. --- ### (i) $$ \lim_{x \to +\infty} \left( \frac{x^2}{8x^2 - 3} \right)^{1/3} $$ Step 1: Divide numerator and denominator by $x^2$, the highest power of $x$: $$ = \left( \frac{x^2}{x^2 \cdot (8 - \frac{3}{x^2})} \right)^{1/3} = \left( \frac{1}{8 - \frac{3}{x^2}} \right)^{1/3} $$ Step 2: Take the limit as $x \to +\infty$: $$ \frac{3}{x^2} \to 0 \Rightarrow 8 _______ ______ _______ _____ ____.
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