Question
Find the equation of the plane which passes through the line of intersection of the planes 3x + 4y - 5z = 9 and 2x+6y+6z = 7 and which is perpendicular to the plane 3x + 2y5z + 6 = 0.
Answer :
Word Count : 405
To find the equation of the required plane, let's follow these steps: ### Step 1: Find the Equation of the Family of Planes The equation of any plane passing through the line of intersection of the given planes: \[ 3x + 4y - 5z = 9 \] \[ 2x + 6y + 6z = 7 \] can be written as: \[ (3x + 4y - 5z - _______ __________ _______ __________ _______.
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To find the equation of the required plane, let's follow these steps: ### Step 1: Find the Equation of the Family of Planes The equation of any plane passing through the line of intersection of the given planes: \[ 3x + 4y - 5z = 9 \] \[ 2x + 6y + 6z = 7 \] can be written as: \[ (3x + 4y - 5z - _______ __________ _______ __________ _______.
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