Find all solutions to the equation sin z = 5

sin z = 5

sin(x+iy) = 5

To solve the equation \(\sin(x+iy) = 5\), we can use the definition of the complex sine function:

\[\sin(z) = \frac{e^{iz} - e^{-iz}}{2i}\]

where \(z = x + iy\). So, we have:

\[\frac{e^{i(x+iy)} - e^{-i(x+iy)}}{2i} = 5\]

Simplify this expression:

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