Question
Expand in a Laurent series valid for
i) ii)
Answer :
Word Count : 376
To find the Laurent series expansion of \( f'(z) = \frac{1}{(z-1)^2 (z-3)} \), we need to expand the function in two different regions: one around \( z = 1 \) and the other around \( z = 3 \). ### i) For \( 0 < |z - 1| < 2 \) In this region, we can treat \( z - 1 \) as small and use the fact that \( \frac{1}{z - 3} \) can be expanded around \( z = 1 \). First, express \( \frac{1}{z - 3} \) as a geometric series: _____ ____ _______ _____ _________ ____ __________.
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To find the Laurent series expansion of \( f'(z) = \frac{1}{(z-1)^2 (z-3)} \), we need to expand the function in two different regions: one around \( z = 1 \) and the other around \( z = 3 \). ### i) For \( 0 < |z - 1| < 2 \) In this region, we can treat \( z - 1 \) as small and use the fact that \( \frac{1}{z - 3} \) can be expanded around \( z = 1 \). First, express \( \frac{1}{z - 3} \) as a geometric series: _____ ____ _______ _____ _________ ____ __________.
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