Question

Expand  f(z)=\frac{1}{(z-1)^{2}(z-3)}      in a Laurent series valid for

(i) 0< \left | z-1 \right |< 2 and

(ii)0< \left | z-3\right |< 2 .

22 Mar 2023
Answer :
Word Count : 387

To find the Laurent series expansion of f(z) = \frac{1}{(z-1)^{2}(z-3)} around different points, we can use partial fraction decomposition to rewrite the function as a sum of simpler terms. Then, we can expand each term as a power series.

First, perform partial fraction decomposition:

f(z) = \frac{A}{(z-1)} + \frac{B}{(z-1)^2} + \frac{C}{(z-3)}

To find the constants A, B, and C, we multiply both sides of the equation by the denominator (z-1)^2(z-3) to clear the fractions:

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