Word Count : 101

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The function ( \frac{1}{z^{2}+1} ) has singularities where ( z^{2}+1=0 ), that is at ( z=i ) and ( z=-i ). Both points satisfy ( __________ ____ ______ ________ _________ _________ ___ ________ ______ ______ _______ _____.
______ ___ _________ ____ ______ ________ ___ ______.
_____ ___ _________ _____ _____ ____ ___ _______.
_____ _________ __________ ________ ________ _____ ________ ____.
_________ ________ __________ _____ __________ ____ _____ ______.
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________ ________ _________ ______ ______ _____ _______ _____ _________ ___.
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