Question
Draw logic circuit for the following Boolean Expression:
Answer :
Word Count : 179
$$ F=(xyz)+(x+y+z)'+(x' z' y') $$ Using De Morgan: $(x+y+z)'=x'y'z'$. The third term $x' z' y'$ is the same as $x'y'z'$. So $$ F=xyz + x'y'z'. $$ Logic-circuit implementation (minimal): * Inputs: x, y, z. * ________ ______ ____ ______ _____ ________.
___ __________ __________ ______ _________ ________ _______ _______ ______ _____ ___.
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____ __________ ________ ___ _____ ______ _____.
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______ ________ ________.
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$$ F=(xyz)+(x+y+z)'+(x' z' y') $$ Using De Morgan: $(x+y+z)'=x'y'z'$. The third term $x' z' y'$ is the same as $x'y'z'$. So $$ F=xyz + x'y'z'. $$ Logic-circuit implementation (minimal): * Inputs: x, y, z. * ________ ______ ____ ______ _____ ________.
___ __________ __________ ______ _________ ________ _______ _______ ______ _____ ___.
___ _________ _________ ______ ______ ________ ____.
_______ ______ _____ _________ ______ __________ ______ ______.
_____ _____ _____ _________ ________ ________ ________.
__________ ________ ______ ___ _________ ______.
___ _______ __________ ________ ____ _____ __________ ___ ______ _____ __________.
______ ____ ______ ______ ______ ____.
_____ ____ _________ ______ _______ __________ _______.
__________ ___ ______ ___ ________ __________ __________ ___ __________.
____ ____ _______ ___ __________ _________.
_________ ______ ___ _____ ____ ______ _______.
_________ _____ __________ ___ _________ ___.
_______ _________ ______ ______ ________ __________.
_____ _____ ________ ________ ______ ______ ___ _________ ____ ________ ____ _________.
__________ _______ ___ _________ ____ _____ _______ ________ _______ __________.
____ __________ ________ ___ _____ ______ _____.
________ ______ ____ ____ ____ _________ ______ ______ _____.
______ ________ ________.
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