Question

Consider the following trial wavefunction for a particle of mass m confined to move in a one-dimensional box of length, L.

ψ = ax(L – x)²
Determine the corresponding energy by using variation theorem. 

22 Aug 2025
Answer :
Word Count : 116
For the trial wavefunction $\psi = ax(L-x)^2$, the normalization constant $a$ is determined from $\int_0^L |\psi|^2 dx = 1$. Expanding $(L-x)^4$ and integrating ____ ___ _____ _________ __________ ____ ____.
____ ___ ________ ____ ________ ___ ____ ________ ________ ________ ______.
_________ _______ ____ __________ _______ ________ _________ __________.
________ _____ _________ ______ ________ _____.
___ __________ ________ _______ ___ _____ ___ _________ ____ ___.
____ __________ _________ ______ _________ ______.
___ ____ _____ _____ _________ _________ ________ ______ _______ ___ ______ ________.
_________ _______ ____ _______ ______ ________ ________ _________ ____.
_______ _______ _____ ________ _________ _____ ___ _____ __________ ________ _______.
____ ____ _____ _________ __________ ____ ________ _____ ___ _____.
__________ ______ _________.
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