Question
Consider a dataset of six points given in the following table, each of which has two features f1 and f2 . Assuming the values of the parameters c and m as 2 and the initial cluster centers v1 = (5,5 ) and v2 (10 ,10, ) , apply FCm algorithm to find the new cluster center after one iteration.
|
| f1 | f 2 |
| x1 | 3 | 11 |
| x 2 | 3 | 10 |
| x3 | 8 | 12 |
| x 4 | 10 | 6 |
| x5 | 13 | 6 |
| x 6 | 13 | 5 |
Answer :
Word Count : 126
Apply FCM with $m=2$. For two clusters the membership $u_{i1}=\dfrac{1}{1+(d_{i1}/d_{i2})^{2}}$ and $u_{i2}=1-u_{i1}$, where $d_{ik}=\|x_i-v_k\|$. Distances to $v_1=(5,5)$ and $v_2=(10,10)$: $x_1=(3,11):\ d_{1,1}=\sqrt{40}\approx6.3249,\ d_{1,2}=\sqrt{50}\approx7.0711\Rightarrow (d_{1,1}/d_{1,2})^2=0.8$ $\Rightarrow u_{1,1}=1/(1+0.8)=5/9\approx0.555556,\ u_{1,2}\approx0.444444.$ $x_2=(3,10):\ d_{2,1}=\sqrt{29}\approx5.3852,\ d_{2,2}=7\Rightarrow (d_{2,1}/d_{2,2})^2=29/49$ $\Rightarrow ___ _______ _______ _____ _____ __________ ______ ____.
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______ ___ ____ _____.
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Apply FCM with $m=2$. For two clusters the membership $u_{i1}=\dfrac{1}{1+(d_{i1}/d_{i2})^{2}}$ and $u_{i2}=1-u_{i1}$, where $d_{ik}=\|x_i-v_k\|$. Distances to $v_1=(5,5)$ and $v_2=(10,10)$: $x_1=(3,11):\ d_{1,1}=\sqrt{40}\approx6.3249,\ d_{1,2}=\sqrt{50}\approx7.0711\Rightarrow (d_{1,1}/d_{1,2})^2=0.8$ $\Rightarrow u_{1,1}=1/(1+0.8)=5/9\approx0.555556,\ u_{1,2}\approx0.444444.$ $x_2=(3,10):\ d_{2,1}=\sqrt{29}\approx5.3852,\ d_{2,2}=7\Rightarrow (d_{2,1}/d_{2,2})^2=29/49$ $\Rightarrow ___ _______ _______ _____ _____ __________ ______ ____.
________ ______ _______ _________ ____ __________ _____ ____ _________ ________.
___ ________ __________ _________ __________ _______ ___ _________ ___ ______ _____ ______.
_________ ____ _________ ______ ___.
___ _______ ____ ______ ______ __________ ______ __________ __________ _____ _____ ____.
__________ _________ ____ ________ ___ _________ __________ __________ ____ _____ _______ __________.
______ ____ ___ ______ ___.
___ ___ ___ _________ ______ ___.
_______ _____ ______ ______ ____ ____ ________ ____ ___ ______.
____ ______ __________ ______ ________ ________ _______ _____ __________ __________ ______.
______ ___ ____ _____.
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