Question
Consider a damped harmonic oscillator whose Lagrangian is given by:
(i) Write the equation of motion and hence obtain the corresponding Hamiltonian.
(ii) Using Hamilton-Jacobi equation associated with the Hamiltonian, solve the equations of motion.
Answer :
Word Count : 556
We will solve this problem step by step. ### Step 1: Write the Equation of Motion The given Lagrangian is: \[ L = e^{bt} \left( \frac{m\dot{q}^2}{2} - \frac{m\omega^2 q^2}{2} \right) \] #### Euler-Lagrange Equation The equation of motion is derived using the Euler-Lagrange equation: \[ \frac{d}{dt} \left( \frac{\partial L}{\partial \dot{q}} \right) - \frac{\partial L}{\partial q} = 0 \] Step 1.1: Compute \(\frac{\partial L}{\partial \dot{q}}\) \[ \frac{\partial L}{\partial \dot{q}} = e^{bt} m \dot{q} \] Taking the time derivative, \[ \frac{d}{dt} \left( e^{bt} m \dot{q} \right) = m e^{bt} \ddot{q} + b m e^{bt} \dot{q} \] Step 1.2: Compute \(\frac{\partial L}{\partial q}\) \[ \frac{\partial L}{\partial q} = -e^{bt} m \omega^2 q \] Thus, the equation of motion is: \[ m e^{bt} \ddot{q} + b m e^{bt} \dot{q} + e^{bt} m \omega^2 q = 0 \] Dividing throughout by \( m e^{bt} ____ ________ ______ __________ ____ _____ _________ _______ _________.
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We will solve this problem step by step. ### Step 1: Write the Equation of Motion The given Lagrangian is: \[ L = e^{bt} \left( \frac{m\dot{q}^2}{2} - \frac{m\omega^2 q^2}{2} \right) \] #### Euler-Lagrange Equation The equation of motion is derived using the Euler-Lagrange equation: \[ \frac{d}{dt} \left( \frac{\partial L}{\partial \dot{q}} \right) - \frac{\partial L}{\partial q} = 0 \] Step 1.1: Compute \(\frac{\partial L}{\partial \dot{q}}\) \[ \frac{\partial L}{\partial \dot{q}} = e^{bt} m \dot{q} \] Taking the time derivative, \[ \frac{d}{dt} \left( e^{bt} m \dot{q} \right) = m e^{bt} \ddot{q} + b m e^{bt} \dot{q} \] Step 1.2: Compute \(\frac{\partial L}{\partial q}\) \[ \frac{\partial L}{\partial q} = -e^{bt} m \omega^2 q \] Thus, the equation of motion is: \[ m e^{bt} \ddot{q} + b m e^{bt} \dot{q} + e^{bt} m \omega^2 q = 0 \] Dividing throughout by \( m e^{bt} ____ ________ ______ __________ ____ _____ _________ _______ _________.
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