Question
Check the continuity and differentiability of the function at (0,0) where
Answer :
Word Count : 587
The given function is defined as: \[ f(x, y) = \left\{ \begin{matrix} \frac{2x^3y}{x^2 + y^2}, & \text{if } (x, y) \neq (0, 0) \\ 0, & \text{if } (x, y) = (0, 0) \end{matrix} \right. \] We need to check the continuity and differentiability of the function at the point \((0, 0)\). ### 1. Checking Continuity at \((0, 0)\): A function is continuous at a point if: \[ \lim_{(x,y) \to (0,0)} f(x, y) = f(0, 0) \] We know that \( f(0, 0) = 0 \). Now we need to check if the limit of \( f(x, y) \) as \( (x, y) \to (0, 0) \) is also \( 0 \). #### Approach along different paths: - Along the x-axis (\( y = 0 \)): \[ f(x, 0) = \frac{2x^3(0)}{x^2 + 0^2} = 0 \] So, as \( x \to 0 \), \( f(x, 0) ________ _________ ____ ____ ____ ____.
_____ _________ _____ _________ __________.
___ _____ _______ _____ ______ _______ ______ ____ _________ ____ ___.
________ _______ _______ ____ _______ ___.
__________ ___ _______ ________ ___ ________ ________ _________ __________ ____ _________ ________.
_____ ____ _________ ____ __________ ___ _____ _________ ______ ______.
_______ ______ ______ ___ ____ ___ __________.
____ _______ ___ _____ ______.
_____ ____ _________ _____ ___ _________.
_____ ___ ___ ___ _______ __________ _______.
______ ______ ______ ___ _______ ________ ______ _____ ___ __________.
_________ _______ __________ ___ _____ ___ ___ ____.
_______ __________ _______ _________ ______ _______.
_______ __________ _____ _______ __________ _____ __________ _______ ______ _____.
_____ ________ _____ _____ ___ _____ ___ ___ ___.
_________ ________ __________ ________ ____ _____ ____ _______ _________ ________.
________ ______ ___ _______ ________ __________ ___ ___ __________ _______.
___ ________ _____ _____ ________ _______ ______ _______ ___.
_______ ___ _______ ________ _________ ________ ________ _______ ___ ________ _____.
____ ___ __________ __________ ___ ______ _____.
________ ___ _________ _______ _____ ____ __________ ______ ________.
___ _________ ___ __________ ________ __________ _________ _______.
_________ __________ ________ _________ ____ ___ ________ ___ __________ _____ __________.
__________ ___ _________ ___ ________ ___ ________ ______ __________ __________ __________.
_______ ___ _______ ________ _________ ______ ______ ________ ____.
____ _______ ____ ____ __________ ________ _______ ________ _____.
________ _______ ___ __________ ______ ___ ________ ____.
________ _______ ____ __________ _____ __________ _____ ____.
_______ ___ _____ ____ ___ ______ ______ ________ ____.
____ ___ __________ ____ ______ _____ ___ __________ __________ ______ _____.
___ _____ __________ ____ ___ ____ ________ ________ ________ ___ __________.
___ ________ _________ ____ __________.
_______ ____ _________ ___ _______ ________.
___ _____ __________ ___ _____ __________ ____ ____.
_____ _____ _______ _____ ______ _________.
__________ _____ ______ _____ _____ __________ _______ _____ _____.
____ _____ _______ _______ ______.
_____ __________ _________ __________ ____ _________ _______ ________ ____ _______ _____ _____.
___ ___ _______ _______ _______ ________ ___ ___ _________.
_________ ______ ___ ___ _______ _____.
________ ____ _________ ______ ____ ___ _______ __________ ____ ___.
____ ___ _______ _________ ____ __________ _______ _______.
_______ ______ _______ ____ ____ _____ ______ ______ ________ __________ ____.
________ ______ ________ ________ ___ ____ _____ _______ ____ ___ _____ ___.
______ __________ ___ _______ _____ ___ _______ ____ ______ _______ ___.
________ ______ __________ ____ __________ _______.
____ ______ ______ ________ ________ ______ _________ ______ ___ ___ ____.
____ _________ _________ ____ ___ _____ ______.
__________ _____ ______ __________ __________ _________ _______ _____ _____ _________ __________ ___.
__________ _________ __________ _________ ________ ________.
_________ _________ _______ _________ _____ ______ ___.
____ __________ ____ _________ ________.
Get Full Answer on WhatsApp
The given function is defined as: \[ f(x, y) = \left\{ \begin{matrix} \frac{2x^3y}{x^2 + y^2}, & \text{if } (x, y) \neq (0, 0) \\ 0, & \text{if } (x, y) = (0, 0) \end{matrix} \right. \] We need to check the continuity and differentiability of the function at the point \((0, 0)\). ### 1. Checking Continuity at \((0, 0)\): A function is continuous at a point if: \[ \lim_{(x,y) \to (0,0)} f(x, y) = f(0, 0) \] We know that \( f(0, 0) = 0 \). Now we need to check if the limit of \( f(x, y) \) as \( (x, y) \to (0, 0) \) is also \( 0 \). #### Approach along different paths: - Along the x-axis (\( y = 0 \)): \[ f(x, 0) = \frac{2x^3(0)}{x^2 + 0^2} = 0 \] So, as \( x \to 0 \), \( f(x, 0) ________ _________ ____ ____ ____ ____.
_____ _________ _____ _________ __________.
___ _____ _______ _____ ______ _______ ______ ____ _________ ____ ___.
________ _______ _______ ____ _______ ___.
__________ ___ _______ ________ ___ ________ ________ _________ __________ ____ _________ ________.
_____ ____ _________ ____ __________ ___ _____ _________ ______ ______.
_______ ______ ______ ___ ____ ___ __________.
____ _______ ___ _____ ______.
_____ ____ _________ _____ ___ _________.
_____ ___ ___ ___ _______ __________ _______.
______ ______ ______ ___ _______ ________ ______ _____ ___ __________.
_________ _______ __________ ___ _____ ___ ___ ____.
_______ __________ _______ _________ ______ _______.
_______ __________ _____ _______ __________ _____ __________ _______ ______ _____.
_____ ________ _____ _____ ___ _____ ___ ___ ___.
_________ ________ __________ ________ ____ _____ ____ _______ _________ ________.
________ ______ ___ _______ ________ __________ ___ ___ __________ _______.
___ ________ _____ _____ ________ _______ ______ _______ ___.
_______ ___ _______ ________ _________ ________ ________ _______ ___ ________ _____.
____ ___ __________ __________ ___ ______ _____.
________ ___ _________ _______ _____ ____ __________ ______ ________.
___ _________ ___ __________ ________ __________ _________ _______.
_________ __________ ________ _________ ____ ___ ________ ___ __________ _____ __________.
__________ ___ _________ ___ ________ ___ ________ ______ __________ __________ __________.
_______ ___ _______ ________ _________ ______ ______ ________ ____.
____ _______ ____ ____ __________ ________ _______ ________ _____.
________ _______ ___ __________ ______ ___ ________ ____.
________ _______ ____ __________ _____ __________ _____ ____.
_______ ___ _____ ____ ___ ______ ______ ________ ____.
____ ___ __________ ____ ______ _____ ___ __________ __________ ______ _____.
___ _____ __________ ____ ___ ____ ________ ________ ________ ___ __________.
___ ________ _________ ____ __________.
_______ ____ _________ ___ _______ ________.
___ _____ __________ ___ _____ __________ ____ ____.
_____ _____ _______ _____ ______ _________.
__________ _____ ______ _____ _____ __________ _______ _____ _____.
____ _____ _______ _______ ______.
_____ __________ _________ __________ ____ _________ _______ ________ ____ _______ _____ _____.
___ ___ _______ _______ _______ ________ ___ ___ _________.
_________ ______ ___ ___ _______ _____.
________ ____ _________ ______ ____ ___ _______ __________ ____ ___.
____ ___ _______ _________ ____ __________ _______ _______.
_______ ______ _______ ____ ____ _____ ______ ______ ________ __________ ____.
________ ______ ________ ________ ___ ____ _____ _______ ____ ___ _____ ___.
______ __________ ___ _______ _____ ___ _______ ____ ______ _______ ___.
________ ______ __________ ____ __________ _______.
____ ______ ______ ________ ________ ______ _________ ______ ___ ___ ____.
____ _________ _________ ____ ___ _____ ______.
__________ _____ ______ __________ __________ _________ _______ _____ _____ _________ __________ ___.
__________ _________ __________ _________ ________ ________.
_________ _________ _______ _________ _____ ______ ___.
____ __________ ____ _________ ________.
Get Full Answer on WhatsApp
IGNOU NEWS
Assignment Submission Last Date Extended Till 30 June 2026 Click Here★★★IGNOU June 2026 TEE Date Sheet Released Click Here★★★