Question
Calculate the relaxation time of electrons in silver assuming that each silver atom contributes one free electron for conduction. The density of silver is 10.5x103 kg m-3 , conductivity of silver is 6.8 x 107Ω⁻¹m⁻¹ and the atomic weight of silver is 107.9 u.
Answer :
Word Count : 549
To calculate the relaxation time of electrons in silver, we can use the Drude model for electrical conduction. The formula for the relaxation time \( \tau \) is: \[ \tau = \frac{m}{n e^2 \rho} \] Where: - \( m \) is the mass of an electron (\(9.11 \times 10^{-31}\) kg), - \( n \) is the number density of conduction electrons (number of conduction electrons per unit volume), - \( e \) is the elementary charge (\(1.6 \times 10^{-19}\) C), - \( \rho \) is the resistivity of the material. We can compute this step by step: ### Step 1: Calculate the number density of conduction electrons, \( n _____ _________ __________ _____ ___ __________ _______.
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To calculate the relaxation time of electrons in silver, we can use the Drude model for electrical conduction. The formula for the relaxation time \( \tau \) is: \[ \tau = \frac{m}{n e^2 \rho} \] Where: - \( m \) is the mass of an electron (\(9.11 \times 10^{-31}\) kg), - \( n \) is the number density of conduction electrons (number of conduction electrons per unit volume), - \( e \) is the elementary charge (\(1.6 \times 10^{-19}\) C), - \( \rho \) is the resistivity of the material. We can compute this step by step: ### Step 1: Calculate the number density of conduction electrons, \( n _____ _________ __________ _____ ___ __________ _______.
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