Question
An individual is handover a bag filled with balls of different colours. The table below gives the probability that a randomly chosen ball is of a specific colour, along with a missing probability value of picking a ball of white colour.
| Colour | Red | Yellow | Green | Orange | Blue | White |
| Probability | 0.2 | 0.2 | 0.1 | 0.1 | 0.1 | ? |
Answer the following questions:
(i) What value must the missing probability be?
(ii) If a ball is drawn at random from the bag, what is the probability of each of the following events?
I. It is either Blue or Red in colour.
II. It is notYellow in colour
III. It is neither Orange nor White in colour. IV. It is either Blue or Red or Yellow or Green or Orange or White
Answer :
Word Count : 368
To solve the problem, let’s break it down step by step. ### (i) What value must the missing probability be? The total probability of all events (in this case, drawing a ball of any color) must sum up to 1. Therefore, we can find the missing probability for the White ball as follows: \[ P(\text{Red}) + P(\text{Yellow}) + P(\text{Green}) + P(\text{Orange}) + P(\text{Blue}) + P(\text{White}) = 1 \] Substituting the given values: \[ ________ _________ __________ _______ _____ _____ _____ _______ _______ ______ _________.
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To solve the problem, let’s break it down step by step. ### (i) What value must the missing probability be? The total probability of all events (in this case, drawing a ball of any color) must sum up to 1. Therefore, we can find the missing probability for the White ball as follows: \[ P(\text{Red}) + P(\text{Yellow}) + P(\text{Green}) + P(\text{Orange}) + P(\text{Blue}) + P(\text{White}) = 1 \] Substituting the given values: \[ ________ _________ __________ _______ _____ _____ _____ _______ _______ ______ _________.
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