Question
A system has seven independent components and reliability block diagram of it shown as follows:
Find reliability of the system.
Answer :
Word Count : 647
Alright — let’s break this down step by step. We have 7 independent components with given reliabilities: \( R_1 = 0.9 \) \( R_2 = 0.8 \) \( R_3 = 0.8 \) \( R_4 = 0.8 \) \( R_5 = 0.9 \) \( R_6 = 0.9 \) \( R_7 = 0.9 \) --- Step 1 — Understand the reliability block diagram from the description From your text, components are grouped as (a, b, c, d): a → series of \( R_1 \) and \( R_2 \) b → series of \( R_3, R_4, R_5 \) c → just \( R_7 \) d → just \( R_6 \) And the system’s connection seems to be: - a, b, c are in parallel (because each is a subsystem), - together in series with d? Or maybe parallel with d? But from typical RBD patterns (and common notation with letters a,b,c,d), a likely configuration is: \[ \text{System} = [ \, \text{(a parallel b parallel ________ _______ ___ _______ ______.
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Alright — let’s break this down step by step. We have 7 independent components with given reliabilities: \( R_1 = 0.9 \) \( R_2 = 0.8 \) \( R_3 = 0.8 \) \( R_4 = 0.8 \) \( R_5 = 0.9 \) \( R_6 = 0.9 \) \( R_7 = 0.9 \) --- Step 1 — Understand the reliability block diagram from the description From your text, components are grouped as (a, b, c, d): a → series of \( R_1 \) and \( R_2 \) b → series of \( R_3, R_4, R_5 \) c → just \( R_7 \) d → just \( R_6 \) And the system’s connection seems to be: - a, b, c are in parallel (because each is a subsystem), - together in series with d? Or maybe parallel with d? But from typical RBD patterns (and common notation with letters a,b,c,d), a likely configuration is: \[ \text{System} = [ \, \text{(a parallel b parallel ________ _______ ___ _______ ______.
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