Question

(a) Show that the perpendiculars drawn from the origin to tangent planes to the cone x^2-y62+5z^2+4xy=0 lie on the cone x^2-y^2+z^2+4xy=0.

11 Mar 2024
Answer :
Word Count : 405
We need to show that the perpendiculars from the origin to the tangent planes of the cone \[ x^2 - y^2 + 5z^2 + 4xy = 0 \] lie on the cone \[ x^2 - y^2 + z^2 + 4xy = 0. \] ### Step 1: Equation of the Tangent Plane to the Given Cone The given cone is: \[ F(x, y, z) = x^2 - y^2 _______ _______ ___ ______ ______ _________ _______ ____.
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